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A runner passes the 2 km mark at 3 o'clock and the 11 km mark at 6 o'clock. What is the runner's average speed during this time period in m/s?

Answer :

The runner's average speed is approximately 0.833 meters per second over a distance of 9 km in 3 hours.

Average speed = total distance / total time.

Step 1: Calculate the total distance.

The runner passes the 2 km mark at 3 o'clock and the 11 km mark at 6 o'clock.

The total distance covered is:

Total distance = 11 km - 2 km

= 9 km

= 9,000 meters.

Step 2: Calculate the total time.

The runner takes 3 hours to cover the distance (from 3 o'clock to 6 o'clock).

Convert time to seconds:

3 hours = 3 * 60 * 60

= 10,800 seconds.

Step 3: Calculate the average speed.

Average speed = total distance / total time

= 9,000 meters / 10,800 seconds

≈ 0.833 meters per second.

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