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Answer :
Energy required for the electronic excitation of Li²⁺ from the first to the third bohr atom is 108.8 eV . The correct answer is option B. 108.8 eV
The energy required for the electronic excitation of a Li²⁻ ion from the first to the third Bohr orbit can be found using the energy level formula for hydrogen-like ions, which is given by the modified Rydberg equation:
E = -Z²Ry(1/n1² - 1/n2²), where Ry is the Rydberg constant for energy, Z is the nuclear charge (for Li²⁻, Z=3), n1 is the initial energy level, and n2 is the final energy level. For the excitation from n=1 to n=3, we plug in the values to get:
E = -3²(-13.6 eV)(1/1² - 1/3²) = -9(-13.6 eV)(1 - 1/9)
E = -9(-13.6 eV)(8/9) = 108.8 eV.
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