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Answer :
Final answer:
To determine the heat transfer required to raise both an aluminum pot's and water's temperature, it is necessary to calculate the heat needed for each using specific heat capacities and add them together. The heat required for the aluminum pot is 36.45 kJ, for the water it is 283.01 kJ, and the total combined is approximately 319.46 kJ, which is not given in the multiple-choice options.
Explanation:
Calculating Heat Transfer
To calculate the heat transfer required to raise the temperature of a 1.50 kg aluminum pot containing 2.50 kg of water from 23.0°C to 50.0°C, we must use the specific heat capacities of aluminum and water. The specific heat capacity of aluminum is 900 J/kg°C, and for water, it is 4186 J/kg°C.
First, calculate the heat transfer for the aluminum pot:
Qaluminum = massaluminum × specific heataluminum × ΔT
Qaluminum = 1.50 kg × 900 J/kg°C × (50.0°C - 23.0°C)
Qaluminum = 1.50 kg × 900 J/kg°C × 27.0°C
Qaluminum = 36,450 J or 36.45 kJ.
Next, calculate the heat transfer for the water:
Qwater = masswater × specific heatwater × ΔT
Qwater = 2.50 kg × 4186 J/kg°C × (50.0°C - 23.0°C)
Qwater = 2.50 kg × 4186 J/kg°C × 27.0°C
Qwater = 283,005 J or 283.01 kJ.
The total heat transfer required is the sum of heat transfer for both the aluminum pot and the water:
Qtotal = Qaluminum + Qwater
Qtotal = 36.45 kJ + 283.01 kJ
Qtotal = 319.46 kJ
Therefore, none of the options (a) 90 kJ, (b) 225 kJ, (c) 180 kJ, (d) 135 kJ is correct; the heat transfer required is approximately 319.46 kJ.
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