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Answer :
Final answer:
To estimate the average weight of men in the United States within 10 pounds with a 90% confidence level, a sample size of 54 is required.
Explanation:
To estimate the average weight of men in the United States within 10 pounds with a 90% confidence level, we can use the formula:
Sample size = (Z * σ / E)²
where Z is the z-score, σ is the standard deviation, and E is the margin of error (10 pounds).
Using the standard normal distribution table, the z-score for a 90% confidence level is approximately 1.645. Substituting the values into the formula:
Sample size = (1.645 * 20 / 10)² = 54.05225 ~ 54
Therefore, a sample size of 54 is required. None of the given options (a, b, c, or d) matches the correct answer.
Learn more about Sample Size Estimation here:
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