Answer :

We are given the function

[tex]$$
f(x) = 5x^4 - 3x^2 + 6x + 2.
$$[/tex]

To find [tex]$f(-2)$[/tex], we substitute [tex]$x = -2$[/tex] into the function:

1. Compute the first term:
[tex]$$
5(-2)^4.
$$[/tex]
Since
[tex]$$
(-2)^4 = 16,
$$[/tex]
then
[tex]$$
5 \times 16 = 80.
$$[/tex]

2. Compute the second term:
[tex]$$
-3(-2)^2.
$$[/tex]
Since
[tex]$$
(-2)^2 = 4,
$$[/tex]
then
[tex]$$
-3 \times 4 = -12.
$$[/tex]

3. Compute the third term:
[tex]$$
6(-2) = -12.
$$[/tex]

4. The constant term remains:
[tex]$$
2.
$$[/tex]

Now, add all the terms together:

[tex]$$
f(-2) = 80 + (-12) + (-12) + 2.
$$[/tex]

Calculate the sum step-by-step:

- [tex]$80 - 12 = 68$[/tex],
- [tex]$68 - 12 = 56$[/tex],
- [tex]$56 + 2 = 58$[/tex].

Thus, the value of [tex]$f(-2)$[/tex] is

[tex]$$
\boxed{58}.
$$[/tex]

Thanks for taking the time to read Given tex f x 5x 4 3x 2 6x 2 tex Find tex f 2 tex A 28 B 10 C 14 D 58 E. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada