Answer :

The z-score corresponding to an observation of 4.7 in a normal distribution with mean 5.7 and standard deviation 0.61 is -1.64.

To find the z-score, we use the formula:

z = (x - μ) / σ

Where:

x = observation (4.7 in this case)

μ = mean of the distribution (5.7 in this case)

σ = standard deviation of the distribution (0.61 in this case)

Substituting the given values into the formula, we get:

z = (4.7 - 5.7) / 0.61

= -1 / 0.61

≈ -1.64

Therefore, the z-score corresponding to an observation of 4.7 is approximately -1.64. This indicates that the observation is 1.64 standard deviations below the mean.

The z-score is a measure of how many standard deviations an observation is from the mean of a distribution. A positive z-score indicates that the observation is above the mean, while a negative z-score indicates that the observation is below the mean.

In this case, the z-score of -1.64 suggests that the observation of 4.7 is below the mean of 5.7. By using z-scores, we can standardize observations and compare them across different distributions or calculate probabilities associated with specific values.

Learn more about z-score here:

brainly.com/question/31871890

#SPJ11

Thanks for taking the time to read x n 5 7 0 61 find the z score corresponding to an observation of 4 7 a 1 64 b 1 64 c 1. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada