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Which of the following selections contain instructions that jump to label L4 only if bits 1, 2, and 3 are all set in the DL register?

A. and dl, 0Eh
test dl, 0Eh
jnz L4

B. test dl, 0Eh
jnz L4

C. and dl, 07h
cmp dl, 07h
je L4

D. and dl, 0Eh
cmp dl, 0Eh
je L4

Answer :

Final answer:

The correct selection that contains instructions to jump to label L4 only if bits 1, 2, and 3 are all set in the DL register is option C: "and dl, 07h cmp dl, 07h je l4."

Explanation:

In option C, the instruction "and dl, 07h" performs a bitwise AND operation between the DL register and the hexadecimal value 07h. This operation sets the ZF (Zero Flag) if bits 1, 2, and 3 in the DL register are all set to 1.

Next, the instruction "cmp dl, 07h" compares the DL register with the value 07h. If they are equal, the ZF is set.

Finally, the instruction "je l4" is a conditional jump instruction that checks the status of the ZF. If the ZF is set (which happens if bits 1, 2, and 3 in DL are all set to 1), it jumps to the label L4.

To clarify further, let's break down the binary representation of 07h: 00000111. In this binary representation, bits 1, 2, and 3 are all set to 1. Therefore, if the DL register also has bits 1, 2, and 3 set to 1, the ZF will be set, and the program will jump to label L4.

In contrast, the other options (A, B, and D) do not perform the necessary bitwise AND operation with 07h to specifically check for these three bits. Therefore, option C is the correct choice.

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