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Answer :
The molarity of NaCl in the solution is 1.997 M.
First, we need to calculate the number of moles of NaCl used in the solution:
moles of NaCl = mass of NaCl / formula mass of NaCl
moles of NaCl = 97.4 g / 58.4 g/mol
moles of NaCl = 1.666 moles
Next, we need to calculate the volume of the solution in liters:
volume of solution = 897 ml ÷ 1000 ml/L
volume of solution = 0.897 L
Finally, we can calculate the molarity using the formula:
molarity = moles of solute / volume of solution
molarity = 1.666 moles / 0.897 L
molarity = 1.997 M
NaCl in the solution therefore has a molarity of 1.997 M.
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