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Answer :
The mass percentage of CaCO₃ in the 3.83 g piece of limestone is 66.8%.
This can be calculated by taking the mass of CaCO₃ (2.57 g) and dividing it by the total mass of limestone (3.83 g) and multiplying by 100.
To calculate this, you need to take the mass of CaCO₃ (2.57 g) and divide it by the total mass of limestone (3.83 g).
This gives you a decimal value, which you then need to multiply by 100 to get the percentage value.
In this case, 2.57/3.83 = 0.668, which multiplied by 100 gives you 66.8%. This is the mass percentage of CaCO₃ in the limestone.
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