Write the abbreviated electron configuration for [tex] \text{Al}^{2+} [/tex].

Question

16-08-2024
Chemistry

High School

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Write the abbreviated electron configuration for [tex] \text{Al}^{2+} [/tex].

Answer :

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pravinmca2002 pravinmca2002 · Answer 1 · 2024-05-03T04:02:09-04:00

Final answer:

The abbreviated electron configuration for Ce3+ is [Xe]4f1 and for Al2+ it is [Ne]3s1. It requires knowing the electron configurations for neutral Ce and Al, and understanding how electrons are removed to form ions.

Explanation:

To write the abbreviated electron configuration for Ce3+, we first need to know the electron configuration of a neutral cerium atom, which is atomic number 58. The electron configuration for Ce is [Xe]6s24f2. When Ce becomes Ce3+, it loses three electrons. These electrons are removed from the 6s and 4f orbitals. Therefore, the abbreviated electron configuration for Ce3+ would be [Xe]4f1. Note that this configuration can be counterintuitive because after losing two 6s electrons, the 4f orbital loses one electron due to 4f being a higher energy level than 6s after lanthanides have more than one electron.

Aluminum (Al), atomic number 13, in its neutral form has the electron configuration: [Ne]3s23p1. When it forms Al2+, it loses two electrons from the 3p and 3s orbitals. Thus, the abbreviated electron configuration of Al2+ is [Ne]3s1. The subject of this question involves determining the electron configuration of Ce3+ and Al2+, which requires an understanding of electron configurations and the principles of how electrons are removed when forming ions.