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Answer :
The confidence interval for the proportion of all California adults (age ≥25) that support Medicare for all, based on the given data, is approximately (0.489, 0.591).
A simple random sample of n=250 California adults (age ≥25) was surveyed, and it was found that 135 of them supported Medicare for all. This data was used to construct a 95% confidence interval for the proportion of all California adults (age ≥25) that support Medicare for all, resulting in the interval.
The confidence interval for the proportion of California adults (age ≥25) that support Medicare for all, based on the provided data, is approximately (0.489, 0.591).
The critical value Z for a 95% confidence level is approximately 1.96 (obtained from the standard normal distribution table).
Plugging in the values, we have:
CI = 0.54 ± 1.96 * sqrt((0.54 * (1 - 0.54)) / 250)
Calculating this expression, we obtain:
CI ≈ (0.489, 0.591)
Therefore, the confidence interval for the proportion of all California adults (age ≥25) that support Medicare for all, based on the given data, is approximately (0.489, 0.591).
It's important to note that the correct confidence interval option from the given choices is (0.489, 0.591).
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