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There are 3.29 g of iodine-126 remaining in a sample originally containing 26.3 g of I-126. The half-life of I-126 is 13 days. How old is the sample?

Answer :

Final answer:

To determine the age of the sample, we can use the formula: ln(Nt/N0) = -kt. Plugging in the values, we can calculate the age of the sample.

Explanation:

To determine the age of the sample, we can use the formula:

ln(Nt/N0) = -kt

Where Nt is the remaining amount of iodine-126, N0 is the initial amount, k is the rate constant, and t is the time.

In this case, Nt = 3.29 g, N0 = 26.3 g, and k is given by the equation:

k = ln(2)/t1/2

Where t1/2 is the half-life of iodine-126. Plugging in the values, we get:

t = - (1/k) * ln(Nt/N0)

Substituting Nt = 3.29 g, N0 = 26.3 g, and k = ln(2)/13 (since the half-life is 13 days), we can calculate the age of the sample.

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