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Answer :
Final answer:
The intensity of Source #2, which has a sound level 2.9 dB greater than Source #1 with an intensity of 36.3 W/m², can be calculated using the formula 10^(ΔdB/10) to find the intensity increase factor. Multiplying this factor with the intensity of Source #1, we find the intensity of Source #2 is approximately 67.84 W/m².
Explanation:
In this question, we are required to identify the sound intensity of Source #2, which is known to be 2.9 dB greater than Source #1. The intensity of Source #1 is 36.3 W/m². From the information at hand, a critical observation is that each factor of 10 in intensity corresponds to an increase of 10 dB in the sound level. However, here the difference is 2.9 dB, which is less than a factor of 10. Therefore, we can't simply multiply the intensity of Source #1 by 10 to find the intensity of Source #2. Instead, we have to calculate the increase factor for the intensity using the formula 10(ΔdB/10), where ΔdB is the difference in decibels. Hence, the factor for an increase of 2.9 dB is 10(2.9/10), which roughly equals to 1.87. Now, we can calculate the intensity of Source #2 by multiplying the intensity of Source #1 by this factor, which gives us roughly 67.84 W/m² as the intensity of Source #2.
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