Answer :

Final answer:

The magnetic field inside a toroid can be calculated using Ampere’s Law. The equation is B = (μ0 × I × N) / (2πr). Without the radius of the toroid, we cannot perform this calculation.

Explanation:

The magnetic field inside a toroid can be calculated using Ampere’s Law for magnetic fields in toroids, which states that the magnetic field (B) is equal to the permeability of free space (μ0) times the current (I) divided by the length of the path around the toroid (2πr), multiplied by the number of turns (N).

The equation is B = (μ0 × I × N) / (2πr).

The value of μ0 is a constant and is typically around 4π × 10^-7 T m/A. Given that the current (I) is 1.69A and the toroid has 372 turns (N), we need to know the radius (r) to calculate the magnetic field (B).

Unfortunately, the radius is not provided in the question, so we can't provide a definite value for the magnetic field. If the radius is known, you can simply plug the values into the equation to calculate the magnetic field.

Learn more about Magnetic Field here:

https://brainly.com/question/36936308

#SPJ11

Thanks for taking the time to read What is the magnitude of the magnetic field inside a 372 turn toroid carrying a current of 1 69 A. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada