High School

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A bottling company marks a 0 for every bottle that comes out correct and a 1 for every defective bottle. Estimate the probability that the next bottle is defective.

Data: [tex]$00000000000000100000$[/tex]

Options:
A. [tex]$\frac{19}{20}$[/tex]
B. [tex]$\frac{1}{20}$[/tex]
C. [tex]$\frac{18}{20}$[/tex]
D. [tex]$\frac{0}{20}$[/tex]

Answer :

To estimate the probability that the next bottle is defective, we need to analyze the data provided by the company. The sequence given is:

`00000000000000100000`

In this sequence, each '0' represents a correctly produced bottle, and each '1' represents a defective bottle.

1. Count the defective bottles: First, we count how many '1's (defective bottles) are in the sequence. In this sequence, there is only 1 defective bottle.

2. Count the total number of bottles: Next, we determine the total number of bottles produced. By counting all the numbers in the sequence, we find that there are 21 bottles in total.

3. Calculate the probability: To find the probability that the next bottle is defective, we divide the number of defective bottles by the total number of bottles:

[tex]\[
\text{Probability of defective bottle} = \frac{\text{Number of defective bottles}}{\text{Total number of bottles}} = \frac{1}{21}
\][/tex]

This fraction simplifies to approximately 0.0476.

Therefore, the probability that the next bottle is defective is about 0.0476. If we express this probability as a fraction from the given options, it matches closely with [tex]\(\frac{1}{20}\)[/tex], which is approximately 0.05, the nearest available choice. Thus, the correct answer is:

[tex]\(\frac{1}{20}\)[/tex]

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