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Answer :
Final answer:
The kinetic energy of a proton traveling at 3125 m/s is approximately 1.62×10⁻²³ Joules, using the kinetic energy formula KE = 1/2 mv².
Explanation:
To calculate the kinetic energy of a proton traveling at a speed of 3125 m/s, you would use the formula for kinetic energy, KE = 1/2 mv², where m is the mass and v is the speed of the proton. A proton has a mass of 1.67×10⁻²⁷ kg. Plugging in the values, we get KE = 1/2 (1.67×10⁻²⁷ kg) (3125 m/s)².
After calculating, you would find that the kinetic energy of the proton is approximately 1.62×10⁻²³ Joules (J), which corresponds to choice (a) from the provided options.
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