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A wheel has an angular acceleration of [tex]5.0 \, \text{rad/s}^2[/tex] and an initial angular speed of [tex]2.00 \, \text{rad/s}[/tex]. In a time of [tex]10 \, \text{s}[/tex], it has rotated through an angle (in radians) of:

Answer :

Final answer:

The wheel, undergoing constant angular acceleration, has rotated through an angle of 270 radians after 10 seconds.

Explanation:

The question asks for the angle a wheel has rotated through given an angular acceleration of 5.0 rad/s² and an initial angular velocity of 2.00 rad/s over a time period of 10 seconds. To solve this, we can use the kinematic equation for rotational motion:

θ = ω₀t + ½ αt²

Where:

  • θ is the angle of rotation in radians
  • ω₀ is the initial angular velocity in rad/s
  • t is the time in seconds
  • α is the angular acceleration in rad/s²

Plugging in the values:

θ = (2.00 rad/s)(10 s) + ½(5.0 rad/s¸)(10 s)²

θ = 20.00 rad + ½(5.0 rad/s²)(100 s²)

θ = 20.00 rad + 250.00 rad

θ = 270.00 rad

Therefore, the wheel has rotated through an angle of 270 radians in 10 seconds under the given conditions.

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