Answer :

multiply everything 1,28x103 then 117x2.93

Thanks for taking the time to read A 1 28 103 kg car accelerates uniformly from rest to 11 7 m s in 2 93 s what is the work done on. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada

To solve this we must be knowing each and every concept related to work and its calculation. Therefore, 439,805 Joules is the work done on the car in this time interval.

What is work?

Work in physics is the energy delivered to or out of an item by applying force across a displacement. It is frequently expressed in its most basic form as the combination of displacement and force.

When a force is applied, it is said to produce positive work if it has a proportion in the orientation of the movement of a site of application. Work done is positive when the direction of force acting on the object and displacement of the object both are in the same direction.

Mathematically,

acceleration=(V-Vo)/t

= (12.4-0)/3.77

= 3.29 m/s^2

d = 0.5×3.29×(3.77)² = 23.37 m

Work = F×d

= (m×g) ×d

=(1920*9.8)23.37

= 439,805 Joules.

Therefore, 439,805 Joules is the work done on the car in this time interval.

To learn more about work, here:

brainly.com/question/18094932

#SPJ5