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Answer :
Let's work through the problem step-by-step.
a. Find the rate of change of Fahrenheit temperature for each unit change in Celsius temperature.
The given data points are:
- When the Celsius temperature is [tex]\(0\)[/tex], the Fahrenheit temperature is [tex]\(32\)[/tex].
- When the Celsius temperature is [tex]\(100\)[/tex], the Fahrenheit temperature is [tex]\(212\)[/tex].
To find the rate of change (or slope), we use the formula for the slope between two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex]:
[tex]\[
\text{Slope} \, m = \frac{y_2 - y_1}{x_2 - x_1}
\][/tex]
Substitute the given points:
[tex]\[
m = \frac{212 - 32}{100 - 0} = \frac{180}{100} = 1.8
\][/tex]
So, the rate of change of Fahrenheit temperature for each unit change in Celsius is [tex]\(1.8\)[/tex] degrees Fahrenheit per degree Celsius.
b. Express the Fahrenheit temperature as a linear function of Celsius temperature, [tex]\(F(C)\)[/tex].
The formula for a linear function is [tex]\(F(C) = m \times C + b\)[/tex], where [tex]\(m\)[/tex] is the slope and [tex]\(b\)[/tex] is the y-intercept. From part (a), we found [tex]\(m = 1.8\)[/tex].
Since we know [tex]\(F(0) = 32\)[/tex], this helps us determine the y-intercept:
[tex]\[
b = 32
\][/tex]
Thus, the function is:
[tex]\[
F(C) = 1.8 \times C + 32
\][/tex]
Find and interpret [tex]\(F(26)\)[/tex]:
To find [tex]\(F(26)\)[/tex] using this function, substitute [tex]\(C = 26\)[/tex]:
[tex]\[
F(26) = 1.8 \times 26 + 32 = 46.8 + 32 = 78.8
\][/tex]
So, when the Celsius temperature is [tex]\(26\)[/tex], the corresponding Fahrenheit temperature is approximately [tex]\(78.8\)[/tex] degrees.
c. Calculate [tex]\(F(-40)\)[/tex]:
Substitute [tex]\(C = -40\)[/tex] into the function:
[tex]\[
F(-40) = 1.8 \times (-40) + 32 = -72 + 32 = -40
\][/tex]
So, [tex]\(F(-40)\)[/tex] is [tex]\(-40\)[/tex] degrees Fahrenheit.
To summarize:
- The rate of change is [tex]\(1.8\)[/tex] degrees Fahrenheit per Celsius degree.
- [tex]\(F(26)\)[/tex] is approximately [tex]\(78.8\)[/tex] degrees Fahrenheit.
- [tex]\(F(-40)\)[/tex] is [tex]\(-40\)[/tex] degrees Fahrenheit.
a. Find the rate of change of Fahrenheit temperature for each unit change in Celsius temperature.
The given data points are:
- When the Celsius temperature is [tex]\(0\)[/tex], the Fahrenheit temperature is [tex]\(32\)[/tex].
- When the Celsius temperature is [tex]\(100\)[/tex], the Fahrenheit temperature is [tex]\(212\)[/tex].
To find the rate of change (or slope), we use the formula for the slope between two points [tex]\((x_1, y_1)\)[/tex] and [tex]\((x_2, y_2)\)[/tex]:
[tex]\[
\text{Slope} \, m = \frac{y_2 - y_1}{x_2 - x_1}
\][/tex]
Substitute the given points:
[tex]\[
m = \frac{212 - 32}{100 - 0} = \frac{180}{100} = 1.8
\][/tex]
So, the rate of change of Fahrenheit temperature for each unit change in Celsius is [tex]\(1.8\)[/tex] degrees Fahrenheit per degree Celsius.
b. Express the Fahrenheit temperature as a linear function of Celsius temperature, [tex]\(F(C)\)[/tex].
The formula for a linear function is [tex]\(F(C) = m \times C + b\)[/tex], where [tex]\(m\)[/tex] is the slope and [tex]\(b\)[/tex] is the y-intercept. From part (a), we found [tex]\(m = 1.8\)[/tex].
Since we know [tex]\(F(0) = 32\)[/tex], this helps us determine the y-intercept:
[tex]\[
b = 32
\][/tex]
Thus, the function is:
[tex]\[
F(C) = 1.8 \times C + 32
\][/tex]
Find and interpret [tex]\(F(26)\)[/tex]:
To find [tex]\(F(26)\)[/tex] using this function, substitute [tex]\(C = 26\)[/tex]:
[tex]\[
F(26) = 1.8 \times 26 + 32 = 46.8 + 32 = 78.8
\][/tex]
So, when the Celsius temperature is [tex]\(26\)[/tex], the corresponding Fahrenheit temperature is approximately [tex]\(78.8\)[/tex] degrees.
c. Calculate [tex]\(F(-40)\)[/tex]:
Substitute [tex]\(C = -40\)[/tex] into the function:
[tex]\[
F(-40) = 1.8 \times (-40) + 32 = -72 + 32 = -40
\][/tex]
So, [tex]\(F(-40)\)[/tex] is [tex]\(-40\)[/tex] degrees Fahrenheit.
To summarize:
- The rate of change is [tex]\(1.8\)[/tex] degrees Fahrenheit per Celsius degree.
- [tex]\(F(26)\)[/tex] is approximately [tex]\(78.8\)[/tex] degrees Fahrenheit.
- [tex]\(F(-40)\)[/tex] is [tex]\(-40\)[/tex] degrees Fahrenheit.
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