Answer :

The area of one of the triangular lateral faces is

[tex]\dfrac{401.48-166.28}6=39.2[/tex]

You're told that the slant height, which is the same as the height of the triangular face, is 9.8, so you have

[tex]39.2=\dfrac12\times9.8\times b[/tex]

where [tex]b[/tex] is the length of the base of the triangle, which is also the same as the side length of the base of the pyramid. So

[tex]b=8[/tex]

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