Answer :

The force needed to bring a car to rest from a speed is 2,541 Newton.

The formula in non-uniform motion

v = u + at

v² = u² + 2ad

[tex]d = u \times t + \frac{1}{2} \times a \times t^2[/tex]

  • u = initial speed (m/s) = 0 m/s
  • v = final speed (m/s) = 85.0 km/h
  • t = time (s)
  • d = displacement (m) = 115 m
  • a = acceleration (m/s)

Because the final speed is km/h, we must convert it into m/s

v = 85.0 km/h

v = [tex]85.0 \times \frac{1 \: km}{1 \: hour}[/tex]

v = [tex]85.0 \times \frac{1,000 \: m}{3,600 \: s}[/tex]

v = [tex]\frac{850}{36}[/tex]

v = 23.6 m/s

Calculate the acceleration

v² = u² + 2ad

23.6² = 0² + (2×a×15)

556.96 = 230a

[tex]a = \frac{556.96}{230}[/tex]

a = 2.42 m/s

Formula to find the force F=ma

  • m = mass (kg) = 1,050 kg
  • a = acceleration(m/s)
  • F = force (Newton)

F = ma

F = 1,050×2.42

F = 2541 Newton

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Rewritten by : Barada