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Answer :
Final answer:
The work done on a proton to move it from a negative plate to a positive plate 4.3 cm away in a field of 125 N/C is calculated as 8.6 x 10^-19 Joules using the formula for work done in an electric field.
Explanation:
To calculate the work done on a proton moving in an electric field, we can use the formula W = Fd, where W is the work done, F is the force, and d is the displacement.
In this case, the force on a proton in an electric field is given by F = Eq, where E is the electric field strength (125 N/C in this case) and q is the charge on the proton (1.6 x 10^-19 C for a proton). So, F = 125 N/C * 1.6 x 10^-19 C = 2.0 x 10^-17 N.
The distance the proton moves is given as 4.3 cm, which is 0.043 m when converted to the SI unit. So, the work done is W = Fd = 2.0 x 10^-17 N * 0.043 m = 8.6 x 10^-19 Joules.
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