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A steel ingot weighing 8000 lb is lifted by a pair of tongs as shown. Determine the forces exerted at points C and E on the tong BCE.

Answer :

The forces exerted at point C and point E on the tong BCE when lifting the steel ingot weighing 8000 lb are 4000 lb and -4000 lb respectively.

To determine the forces exerted at points C and E on the tong BCE when lifting a steel ingot weighing 8000 lb, we can use the principles of static equilibrium.

First, let's assume that the force exerted at point C is FC and the force exerted at point E is FE. Since the ingot is in static equilibrium, the sum of the forces acting on it in both the horizontal and vertical directions must be zero.

In the vertical direction, we have the weight of the ingot acting downward, which is 8000 lb. This force is balanced by the combined vertical forces at points C and E. So we can write:

FC + FE = 8000 lb

In the horizontal direction, we can assume that there is no horizontal force acting on the ingot, so the sum of the horizontal forces at points C and E must also be zero. This implies that the horizontal component of the force at point C is equal in magnitude and opposite in direction to the horizontal component of the force at point E.

Now, let's break down the forces at points C and E into their horizontal and vertical components. We can use trigonometry to find these components.

At point C, let's assume the angle between the horizontal direction and the force FC is θ. The horizontal component of FC is FC * cos(θ) and the vertical component is FC * sin(θ).

Similarly, at point E, the horizontal component of FE is FE * cos(θ) and the vertical component is FE * sin(θ).

Since the horizontal forces at points C and E are equal in magnitude and opposite in direction, we have:

FC * cos(θ) = -FE * cos(θ)

Simplifying this equation, we find:

FC = -FE

Substituting this result into the equation FC + FE = 8000 lb, we get:

FC + FC = 8000 lb
2FC = 8000 lb
FC = 4000 lb

So the force exerted at point C is 4000 lb and the force exerted at point E is -4000 lb. The negative sign indicates that the force at point E is in the opposite direction compared to the force at point C.

In summary, the forces exerted at point C and point E on the tong BCE when lifting the steel ingot weighing 8000 lb are 4000 lb and -4000 lb respectively.

Learn more about forces from the given link

https://brainly.com/question/12785175

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