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Answer :
Final answer:
The mass of the lead piece displaced, multiply the density of lead by the displaced volume. In this case, the mass of the lead piece is 39.3 grams, hence correct answer is A) 39.3 g.
Explanation:
Density (ρ) relates the mass (m) of an object to its volume (V) by the formula:
ρ = m / V
We are given the:
Density of lead (ρ) = 11.3 g/ml
Volume of water displaced (V) = 3.48 ml (Note that water and lead have the same density in this context, but it's not required for the solution)
We need to find the mass (m) of the lead.
Rearrange the formula to solve for mass:
m = ρ * V
Plug in the known values:
m = (11.3 g/ml) * (3.48 ml)
Calculate the mass:
m ≈ 39.324 g
Round to two significant digits (same number of significant digits as the least precise measurement, which is 3.48 ml):
m ≈ 39.3 g
Therefore, the mass of the lead is approximately 39.3 grams. The answer is (A).
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