We appreciate your visit to An attack helicopter is equipped with a 20 mm cannon that fires 187 g shells in the forward direction with a muzzle speed of 985. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
The resulting average force on the helicopter is approximately 198,763 N.
To find the resulting average force on the helicopter, we need to consider the momentum change caused by the fired shells.
The momentum change can be calculated using the formula: Δp = m * Δv, where Δp is the change in momentum, m is the mass of the shells, and Δv is the change in velocity.
The mass of each shell is given as 187 g, which is equivalent to 0.187 kg. The change in velocity is the difference between the muzzle speed of 985 m/s and the final velocity, which is zero since the shells are fired in the forward direction.
The change in momentum for each shell is Δp = (0.187 kg) * (985 m/s - 0 m/s) = 184.295 kg·m/s.
The total change in momentum for the burst of 109 shells is then Δp_total = (109 shells) * (184.295 kg·m/s) = 20,083.155 kg·m/s.
According to Newton's third law of motion, for every action, there is an equal and opposite reaction. Thus, the momentum change of the shells results in an equal and opposite momentum change for the helicopter.
The mass of the fully loaded helicopter is given as 2640 kg, so the change in velocity for the helicopter can be calculated as Δv_helicopter = Δp_total / m_helicopter = 20,083.155 kg·m/s / 2640 kg = 7.61 m/s.
Using the formula F = Δp / Δt, where F is the force, Δp is the momentum change, and Δt is the time interval, we can calculate the average force on the helicopter.
The time interval is given as 3.78 s, so the average force is F = 20,083.155 kg·m/s / 3.78 s = 5,303.97 N.
However, this force is the force exerted by the shells on the helicopter. To find the resulting average force on the helicopter itself, we need to consider the mass of the helicopter and the acceleration due to the change in velocity.
The resulting average force on the helicopter is then F_resultant = m_helicopter * Δv_helicopter / Δt = 2640 kg * 7.61 m/s / 3.78 s ≈ 198,763 N.
Therefore, the resulting average force on the helicopter is approximately 198,763 Newtons.
To know more about force, refer here:
https://brainly.com/question/30507236#
#SPJ11
Thanks for taking the time to read An attack helicopter is equipped with a 20 mm cannon that fires 187 g shells in the forward direction with a muzzle speed of 985. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!
- Why do Businesses Exist Why does Starbucks Exist What Service does Starbucks Provide Really what is their product.
- The pattern of numbers below is an arithmetic sequence tex 14 24 34 44 54 ldots tex Which statement describes the recursive function used to..
- Morgan felt the need to streamline Edison Electric What changes did Morgan make.
Rewritten by : Barada
