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Answer :
Since the denominator is zero, which means that direct substitution cannot be used to find the limit and the limit is undefined.
The given function is:
[tex]\lim_{x \to 1}[/tex] (x – 8x +9)/ (2x-2)
To do this, substitute the value of x directly into the expression and evaluate it.
Plugging in x = 1, we have:
(1 – 8(1) + 9) / (2(1) - 2)
Simplifying the numerator and denominator, we get:
(1 – 8 + 9) / (2 - 2)
Combining like terms, we have:
(2) / (0)
Since, the denominator is zero, which means that direct substitution cannot be used to find the limit.
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The complete question is:
Find the limit by direct substitution. Find the limit by direct substitution. [tex]\lim_{x \to 1}[/tex] (x – 8x +9)/ (2x-2)
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