High School

We appreciate your visit to What is the change in freezing point for a solution that contains 235 g of solute dissolved in 1 20 kg of water. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!

What is the change in freezing point for a solution that contains 235 g of solute dissolved in 1.20 kg of water?

Answer :

Answer:

T° Freezing solution = - 2.91°C

Explanation:

To solve this, we apply this formula:

ΔT = Kf . m . i

Our solute is SnI₄

ΔT = Freezing T° of pure solvent - Freezing T° of solution

m is molality

i, numbers of ions dissolved.

SnI₄ → Sn⁴⁺ + 4I⁻

5 moles of ions have been formed, 1 mol of Sn⁴⁺ and 4 moles of iodide.

Let's determine molality. Firstly we need the moles of salt.

235 g . 1mol / 626.3 g = 0.375 moles

molality = mol /kg of solvent → 0.375 mol /1.20kg = 0.313 m

Kf reffers to Cryoscopic constant, for water is 1.86°C/m. We replace data at formula → 0°C - T°F solution = 0.313 m . 1.86°C/m . 5

T°F solution = - 2.91°C

Thanks for taking the time to read What is the change in freezing point for a solution that contains 235 g of solute dissolved in 1 20 kg of water. We hope the insights shared have been valuable and enhanced your understanding of the topic. Don�t hesitate to browse our website for more informative and engaging content!

Rewritten by : Barada