We appreciate your visit to Light of wavelength 500 nm illuminates a round 0 50 mm diameter hole A screen is placed 6 0 m past the slit What is. This page offers clear insights and highlights the essential aspects of the topic. Our goal is to provide a helpful and engaging learning experience. Explore the content and find the answers you need!
Answer :
The width of the central bright circle on the screen is approximately 114.6°,
To find the width of the central bright circle on the screen, we can use the formula for the angular width of a single-slit diffraction pattern:
θ = 2λ/a
Where θ is the angular width, λ is the wavelength of light, and a is the width of the slit. In this case, the wavelength is given as 500 nm and the diameter of the hole is given as 0.50 mm. To convert the diameter to width, we divide it by 2: 0.50 mm / 2 = 0.25 mm
= 250 μm. Now we can plug in these values into the formula:
θ = 2(500 nm) / 250 μm
= 2 radians
Since the angular width is in radians, we can convert it to degrees by multiplying by
180/π: 2 radians * (180/π) = 114.6°.
Thus, the width of the central bright circle on the screen is approximately 114.6°.
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