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A 36 kg glider is gliding through the air at a height of 467 meters with a speed of [tex]$58 \, \text{m/s}$[/tex]. The glider dives to a height of 245 meters. What is the glider's new velocity?

Answer :

Final answer:

To find the glider's new velocity, we can use the principle of conservation of energy. Given the initial height, final height, and initial velocity, we can solve for the final velocity using the equation ΔPE = 0.5mv1^2 - 0.5mv2^2.

Explanation:

To find the glider's new velocity, we can use the principle of conservation of energy. Initially, the glider has potential energy and kinetic energy, given by mgh and 0.5mv^2 respectively. When the glider dives to a lower height, it loses potential energy but gains kinetic energy. The change in potential energy is given by ΔPE = mgh1 - mgh2, and the change in kinetic energy is ΔKE = 0.5mv1^2 - 0.5mv2^2. Since energy is conserved, ΔPE = -ΔKE. We can solve for v2 using the equation ΔPE = 0.5mv1^2 - 0.5mv2^2.

Given the values, m = 36 kg, h1 = 467 m, h2 = 245 m, and v1 = 58 m/s, we can plug these values into the equation to calculate v2.

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