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Answer :
To stop a 1200 kg car moving at 99 km/h in a straight path,
the work that must be done in Joules is 453750.
Step-by-step Given,
Mass of car, m = 1200 kg
Initial velocity, u = 99 km/h = 27.5 m/s
Final velocity, v = 0 m/s (as the car is brought to rest)
Initial kinetic energy, K.E1 = 1/2 m u²
Final kinetic energy, K.E2 = 1/2 m v²
Work done to bring the car to rest,
W = K.E1 - K.E2W
= 1/2 m u² - 1/2 m v²W
= 1/2 × 1200 × (27.5)² - 1/2 × 1200 × (0)²W
= 1/2 × 1200 × (27.5)²W
= 453750 J
Therefore, the work that must be done in Joules to stop the car is 453750.
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