Answer :

Final answer:

To cover 12 positions 8 hours a day for 7 days a week, it would require 672 total hours per week. With one FTE representing a 40-hour workweek, this equates to 16.8 FTEs. After rounding up, it takes 17 full-time equivalents to cover the schedule.

Explanation:

To determine how many full-time equivalents (FTEs) are needed to cover 12 positions for 8 hours a day, 7 days a week, we should start by calculating the total number of hours required per week. Since one position requires 8 hours per day, and there are 7 days in a week, each position requires 56 hours per week (8 hours per day * 7 days). Multiplying this by 12 positions, we need a total of 672 hours per week (56 hours * 12 positions).

Next, we should consider what constitutes a full-time equivalent. Typically, one FTE represents a full-time workweek. Based on the Bureau of Labor Statistics, the average full-time workweek is around 40 hours. Thus, to find the number of FTEs needed, we divide the total weekly hours by 40 hours per FTE. Doing the calculation, we get 16.8 FTEs (672 hours / 40 hours per FTE).

However, since we cannot employ a fraction of a person, we would need to round up to the nearest whole number. Therefore, it would take 17 full-time equivalents to cover 12 positions, 8 hours a day, 7 days per week.

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