High School

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Use a model for body surface area (BSA), such that

\[ \text{BSA} = \sqrt{\frac{wh}{3600}}, \]

where \( w \) is weight in kg and \( h \) is height in cm. Find the weight of a 173-cm male to the nearest kg whose BSA is 2.1.

Answer :

The weight of the 173-cm male to the nearest kg is 44 kg.

Let's find the weight of a 173-cm male to the nearest kg whose bsa = 2.1. We're given the formula for body surface area, bsa, such that bsa = wh 3600 , where w = weight in kg and h = height in cm.

We can solve the equation for w by following these steps:

1. Multiply both sides of the equation by 3600 to eliminate the fraction denominator.

2. Multiply both sides of the equation by 173 to eliminate the w denominator.

3. Divide both sides of the equation by 173 to isolate w.

Steps to solve:

**1. Multiply both sides of the equation by 3600 to eliminate the fraction denominator:**

[tex]3600 \cdot 2.1=3600 \cdot \frac{173w}{3600}[/tex]

**2. Cancel multiplied terms that are in the denominator:**

[tex]3600 \cdot 2.1=173w[/tex]

**3. Multiply both sides of the equation by 173 to eliminate the w denominator:**

7560=173w

**4. Divide both sides of the equation by 173 to isolate w:**

[tex]\frac{7560}{173}=\frac{173w}{173}[/tex]

**5. Simplify:**

w=43.699421965

**Answer:**

The weight of the 173-cm male to the nearest kg is 44 kg.

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