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Answer :
Final answer:
The corresponding frequency of the sinewave is approximately 1.55 MHz.
Explanation:
The period of a sinewave is the time it takes for one complete cycle. Frequency, on the other hand, is the number of cycles per unit time. The relationship between period and frequency is given by the equation:
T = 1/f
In this case, the period of the sinewave is 645 μs. To find the corresponding frequency, we can rearrange the equation to solve for f:
f = 1/T
Substituting the given value for the period:
f = 1/(645 × 10^-6 s)
Calculating this expression gives us:
f ≈ 1.55 MHz
Therefore, the corresponding frequency of this sinewave is option b) 1.55 MHz.
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