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When 1.57 mol of [tex]O_2[/tex] reacts with [tex]H_2[/tex] to form [tex]H_2O[/tex], how many moles of [tex]H_2[/tex] are consumed in the process?

Answer :

Consult the balanced reaction:

O₂ + 2 H₂ ⇄ 2 H₂O

which says you need twice as many moles of H₂ as O₂. So if 1.57 mol O₂ is available, then the reaction would consume 2 × 1.57 = 3.14 mol H₂.

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