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A cell can be considered a sphere with radius r=12.0μm, surrounded by a membrane with thickness x=42 A˚. Na+ions flow into the cell from the medium at a rate 2×1010 ions per 1 ms.Na+concentrations at both sides of the membrane are [Na+]out ​=120mM and [Na+]in ​=12mM. The diffusion coefficient of Na+inside the membrane is 5.2×10−10 m2/s. Find the partition coefficient of Na+ions between the membrane and the medium. Seven consecutive tRNAs during protein biosynthesis have the following anticodons: UCC, CUU, GUA, UGA, CUG, AUU, GAA. Provide the sequence of the resulting amino acid chain.

Answer :

Final answer:

The partition coefficient of Na+ ions between the membrane and the medium is 0.1. The sequence of the resulting amino acid chain from the given tRNA anticodons is: Serine, Leucine, Valine, Stop codon, Leucine, Isoleucine, Glutamic acid.

Explanation:

To find the partition coefficient of Na+ ions between the membrane and the medium, we can use the formula:

Partition Coefficient = [Na+]in / [Na+]out

Given:

  • Na+ concentrations at both sides of the membrane are [Na+]out = 120mM and [Na+]in = 12mM.

Substituting the given values into the formula:

Partition Coefficient = 12mM / 120mM = 0.1

Therefore, the partition coefficient of Na+ ions between the membrane and the medium is 0.1.

The sequence of the resulting amino acid chain from the given tRNA anticodons is:

  1. UCC - Serine
  2. CUU - Leucine
  3. GUA - Valine
  4. UGA - Stop codon
  5. CUG - Leucine
  6. AUU - Isoleucine
  7. GAA - Glutamic acid

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