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A person's heartbeat is 80 beats per minute. If his/her heart beats [tex]3.1 \times 10^9[/tex] times in a lifetime, how long (in whole years) does the person live? Disregard leap years.

Answer :

The person will live 73.62 years

The heartbeats 80 times in 1 minute

Therefore , 1 heartbeat takes [tex]1/80 minutes[/tex] time

In whole life number of heartbeats = [tex]3.1* 10^{9}[/tex]

Thus, time in which [tex]3.1* 10^{9}[/tex] heart beat will occur = [tex]3.1* 10^{9} * 1/80 minutes[/tex]

= [tex]0.03875 * 10^{9}[/tex] minutes

Since 1 minutes =[tex]1.90259 * 10^{-6}[/tex] year

Therefore, [tex]0.3875 * 10^{9}[/tex] minutes = [tex]0.03875 * 10^{9}[/tex] * [tex]1.90259 * 10^{-6}[/tex] year

= [tex].073625* 10^3[/tex] years

= 73.62 years

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