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If EF = 117 , FG = 100, EG = 94, IJ = 40 , and HJ = 37.6 , find the perimeter of HIJ. Round your answer to the nearest tenth if necessary. Figures are not necessarily drawn to scale.

If EF 117 FG 100 EG 94 IJ 40 and HJ 37 6 find the perimeter of HIJ Round your answer to the nearest tenth

Answer :

Answer:

124.4

Step-by-step explanation:

Perimeter of ∆HIJ = IJ + HJ + HI

IJ = 40

HJ = 37.6

HI = ?

Let's find HI

∆HIJ and ∆EFG are similar. Since they have equal corresponding angles. Therefore, the ratio of their corresponding sides would be equal.

Thus:

EF/HI = FG/IJ

EF = 117 (given)

HI = ?

FG = 100 (given)

IJ = 40 (given)

Plug in the values

117/HI = 100/40

117/HI = 2.5

117 = HI*2.5

117/2.5 = HI

HI = 46.8

✔️Perimeter of ∆HIJ = IJ + HJ + HI

= 40 + 37.6 + 46.8

= 124.4

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