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Answer :
Answer:
The rocket will take 9.25 seconds to return to ground
.
Solution:
Given:
Initial velocity = 148 ft per seconds
Height "h" after "t" seconds is given by equation:
[tex]h(t) = -16t^2 + 148t[/tex]
To find:
Time taken by rocket to return to ground =?
Solution:
The time taken by rocket to return to ground can found by substituting h(t) = 0 in the given equation.
[tex]0 = -16t^2 + 148t[/tex]
Taking t outside
t(-16t + 148) = 0
Zero product property. The zero product property states that if a⋅b = 0 then either a or b equal zero. This basic property helps us solve equations like (x+2)(x-5) = 0
So for above equation we get,
t =[tex]0 \text{ or } -16t + 148 = 0[/tex]
[tex]-16t + 148 = 0[/tex]
[tex]-16t = -148[/tex]
t = 9.25
When t = 0 , the rocket would not left the ground. So ignore t = 0
So t = 9.25
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Final answer:
The rocket will take approximately 9.25 seconds to return to the ground.
Explanation:
To find the time it will take for the rocket to return to the ground, we need to determine when the height of the rocket, h(t), equals zero. Given the equation h(t) = -16t^2 + 148t, we can set it equal to zero and solve for t.
First, we set -16t^2 + 148t = 0 and factor out -4t: -4t(4t - 37) = 0. This equation equals zero when -4t = 0 or 4t - 37 = 0. Solving, we find t = 0 and t = 9.25.
Since time cannot be negative, we can ignore t = 0. Therefore, it will take the rocket approximately 9.25 seconds to return to the ground.
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