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A 35.8 g sample of halothane is 0.181 moles. At STP, what is the concentration (% v/v) of 35.8 g of halothane that has been completely vaporized into a container with a volume of 224 L? Assume that halothane is an ideal gas.

Answer :

Final answer:

To find the concentration (% v/v) of halothane in a container, calculate the molar concentration and convert it to a percent volume concentration.

Explanation:

To find the concentration (% v/v) of halothane in the container, we need to calculate the molar concentration of halothane first. From the given information, we know that a 35.8 g sample of halothane is 0.181 moles.

Now, we need to find the volume of the container in liters. Given that the volume is 224 L, we can divide the moles of halothane by the volume to find the molar concentration.

Molar concentration = Moles/Volume = 0.181 moles/224 L = 0.000808 M

Finally, to convert the molar concentration to a percent volume concentration, we can divide the Molar concentration by the molar mass of halothane and multiply by 100.

Percent volume concentration = (Molar concentration/molar mass) x 100 = (0.000808 M/197.37 g/mol) x 100 = 0.0004105%

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