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Answer :
[tex]d=2r\\
d=22\\
2r=22\\
r=11\ inches\\
\\
A=\pi r^2\\
A=\pi \cdot 11^2=3,14 \cdot 121=379,94\ inch^2[/tex]
d=22\\
2r=22\\
r=11\ inches\\
\\
A=\pi r^2\\
A=\pi \cdot 11^2=3,14 \cdot 121=379,94\ inch^2[/tex]
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Rewritten by : Barada
[tex]R=\frac{Diameter}{2}[/tex]
then
[tex]R=\frac{22~in}{2}[/tex]
[tex]\boxed{R=11~in}[/tex]
now we just need to apply this formula
[tex]S=\pi*R^2[/tex]
[tex]S=\pi*11^2[/tex]
[tex]\boxed{\boxed{S=121*\pi~in^2}}[/tex]
then
[tex]R=\frac{22~in}{2}[/tex]
[tex]\boxed{R=11~in}[/tex]
now we just need to apply this formula
[tex]S=\pi*R^2[/tex]
[tex]S=\pi*11^2[/tex]
[tex]\boxed{\boxed{S=121*\pi~in^2}}[/tex]
