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Answer :
To find [tex]\( f(3) \)[/tex] for the function [tex]\( f(x) = -5x^2 - x + 20 \)[/tex], you follow these steps:
1. Substitute [tex]\( x = 3 \)[/tex] into the function:
[tex]\[
f(3) = -5 \times (3)^2 - (3) + 20
\][/tex]
2. Calculate [tex]\( 3^2 \)[/tex]:
[tex]\[
3^2 = 9
\][/tex]
3. Multiply by [tex]\(-5\)[/tex]:
[tex]\[
-5 \times 9 = -45
\][/tex]
4. Substitute all values into the expression:
[tex]\[
f(3) = -45 - 3 + 20
\][/tex]
5. Perform the arithmetic:
- First, combine [tex]\(-45\)[/tex] and [tex]\(-3\)[/tex]:
[tex]\[
-45 - 3 = -48
\][/tex]
- Then add 20:
[tex]\[
-48 + 20 = -28
\][/tex]
Hence, the value of [tex]\( f(3) \)[/tex] is [tex]\(-28\)[/tex].
1. Substitute [tex]\( x = 3 \)[/tex] into the function:
[tex]\[
f(3) = -5 \times (3)^2 - (3) + 20
\][/tex]
2. Calculate [tex]\( 3^2 \)[/tex]:
[tex]\[
3^2 = 9
\][/tex]
3. Multiply by [tex]\(-5\)[/tex]:
[tex]\[
-5 \times 9 = -45
\][/tex]
4. Substitute all values into the expression:
[tex]\[
f(3) = -45 - 3 + 20
\][/tex]
5. Perform the arithmetic:
- First, combine [tex]\(-45\)[/tex] and [tex]\(-3\)[/tex]:
[tex]\[
-45 - 3 = -48
\][/tex]
- Then add 20:
[tex]\[
-48 + 20 = -28
\][/tex]
Hence, the value of [tex]\( f(3) \)[/tex] is [tex]\(-28\)[/tex].
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