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Answer :
Final answer:
The acceleration of the airplane, considering a tailwind that boosts its speed for 69 km, is found to be 0.13 m/s^2.
This is obtained by first converting the given speeds to m/s, solving for time using kinematics equation, and then substitifying time into acceleration equation.
Explanation:
The question involves concepts from physics, specifically kinematics.
The acceleration of an object is calculated using the formula a = (v_f - v_i) / t,
where a = acceleration, v_f = final velocity, v_i= initial velocity and t = time.
But in this particular question, time is unknown.
However, we can use another kinematics equation d = v_i * t + 0.5 * a * t^2 ,
where d=distance traveled, to solve for the time first, and then use it in the first equation to find the acceleration.
Converting the speed from km/hr to m/s, we get initial speed as 214 m/s and final speed as 253.6 m/s.
Distance covered is 69000m.
Solving the second equation for time, assuming uniform acceleration (a), we get t approximately to be 306.19s.
Then substituting the obtained time value into the first equation, we get acceleration a to be 0.13 m/s².
Learn more about Acceleration calculation here:
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