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Answer :
the correct option is c. 0.46.
The expected frequency of heterozygotes in the next generation can be calculated using the Hardy-Weinberg equation, which is expressed as:
p^2 + 2pq + q^2 = 1
where p is the frequency of the dominant allele and q is the frequency of the recessive allele.Given that the frequency of dominant alleles is 0.36 and the frequency of recessive alleles is 0.64, we can determine the frequency of heterozygotes as follows:
q^2 = (0.64)2 = 0.4096p^2 = (0.36)2 = 0.1296.
Since the sum of the frequencies of homozygous dominant, homozygous recessive, and heterozygous individuals must equal 1, we can solve for the frequency of heterozygotes by subtracting the frequencies of the other two genotypes from 1.2pq = 1 - p^2 - q^2 = 1 - 0.1296 - 0.4096 = 0.4608.
Therefore, the expected frequency of heterozygotes in the next generation is 0.4608, which is approximately 0.46. Hence, the correct option is c. 0.46.
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