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Answer :
Final answer:
By setting up and solving a system of equations, we find the prices for individual goldfish and hermit crabs, and use those to calculate the total price for 6 goldfish and 4 hermit crabs, which is $28.
Explanation:
To solve the problem, we need to set up a system of equations based on the given information. Let's denote G as the price of one goldfish and H as the price of one hermit crab.
- For 7 goldfish and 3 hermit crabs, the total is $26. Therefore, the equation is 7G + 3H = 26.
- For 4 goldfish and 5 hermit crabs, the total is $28. Therefore, the equation is 4G + 5H = 28.
We can solve these two equations using the method of substitution or elimination. For this instance, we will use the elimination method:
- Multiply the first equation by 4 and the second by 7 to make the coefficients of G the same:
- 28G + 12H = 104
(First equation multiplied by 4) - 28G + 35H = 196
(Second equation multiplied by 7) - Subtract the first new equation from the second to eliminate G:
- 23H = 92
- Divide both sides by 23 to find H:
- H = 4
- Substitute H back into one of the original equations to find G:
- 7G + 3(4) = 26
7G + 12 = 26
7G = 14
G = 2
Now that we have the price for each goldfish and hermit crab, we can calculate the cost for 6 goldfish and 4 hermit crabs: 6G + 4H = 6(2) + 4(4) = 12 + 16 = 28.
The store would sell 6 goldfish and 4 hermit crabs for $28.
The answer is C. $28.
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