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What is the Molarity of a solution which contains 0.120 moles of CH3COOH in 1.55 L? 0 0.077 M CH3COOH 1.07 M CH3COOH 12.92 M CH3COOH C 0.885 M CH3COOH o 0.933 M CH3COOH

Answer :

Final answer:

The molarity of the solution is approximately 0.077 M CH3COOH.

Explanation:

To calculate the molarity of a solution, we need to use the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

In this case, we are given that the solution contains 0.120 moles of CH3COOH and has a volume of 1.55 L.

Substituting these values into the formula, we get:

Molarity (M) = 0.120 moles / 1.55 L

Calculating this, we find that the molarity of the solution is approximately 0.077 M CH3COOH.

Learn more about calculating molarity of a solution here:

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