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A special "cell" contains 1% starch, 5% glucose, and 94% water. It has a semipermeable membrane that is permeable to water, sodium, and glucose but not to starch. This cell is placed in a beaker with a solution containing 1% starch and 5% sodium.

What substance(s) show net movement into the cell?

Answer :

Final answer:

In the given scenario, water and sodium would show net movement into the 'cell'. This is driven by the rules of osmosis and the specific permeability of the cell's membrane, which allows sodium but not starch to enter.

Explanation:

The substances that would show net movement into the special 'cell' in question, based on the given scenario, are water and sodium. This is due to the concept of osmosis and the permeability of the cell's semipermeable membrane.

Net movement of substances is driven by differences in concentration. Given the cell's environment, water would move into the cell because there is a higher concentration of solute (starch and sodium) outside the cell, while the cell contains mostly water. However, since the cell's membrane is not permeable to starch, only sodium will enter the cell due to the concentration gradient, where it is 5% outside versus 0% inside the cell. No glucose would move out of the cell because the environment outside the cell isn't usually described as containing any glucose.

Learn more about Osmosis here:

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