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When an electron jumps between the following shells, the wavelengths of the radiations emitted are:

- From the 2nd to the 1st shell: [tex]\lambda_1[/tex]
- From the 3rd to the 2nd shell: [tex]\lambda_2[/tex]
- From the 3rd to the 1st shell: [tex]\lambda_3[/tex]

What is the relationship between these wavelengths?

Answer :

The wavelength relationship for electron transitions in a hydrogen atom is λ₃ < λ₁ < λ₂, with λ₃ being the shortest wavelength for the 3rd to 1st transition and λ₂ the longest for the 3rd to 2nd transition.

To understand the relationship between these wavelengths, we need to delve into the Bohr model of the atom and the concept of energy levels in hydrogen atoms. According to the Bohr model:

  • The energy of an electron in the nth orbit of a hydrogen atom is given by: Eₙ = -13.6 eV/n²
  • The wavelength (λ) of the emitted photon when an electron transitions from a higher energy level (n₂) to a lower one (n₁) can be found using the Rydberg formula: 1/λ = R(1/n₁² - 1/n₂²) where R is the Rydberg constant (1.097 × 10⁷ m⁻¹)

Given the transitions:

  • For the transition from the 2nd to 1st shell (n₂=2 to n₁=1): 1/λ₁ = R(1/1² - 1/2²) = R(1 - 1/4) = 3R/4
  • For the transition from the 3rd to 2nd shell (n₂=3 to n₁=2): 1/λ₂ = R(1/2² - 1/3²) = R(1/4 - 1/9) = 5R/36
  • For the transition from the 3rd to 1st shell (n₂=3 to n₁=1): 1/λ₃ = R(1/1² - 1/3²) = R(1 - 1/9) = 8R/9

From these equations, we can see the relationship:

  • λ₃ < λ₁ < λ₂ since 8R/9 > 3R/4 > 5R/36.

This demonstrates that the wavelength of radiation emitted is inversely proportional to the energy difference between the two levels.

Complete Question:

When an electron jumps from 2nd to 1st, 3rd to 2nd, and 3rd to 1st shells, the wavelength of radiations emitted is λ₁, λ₂, λ₃, respectively. The relationship between wavelengths is?

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