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Write a function to describe the following scenario:

A garden watering bucket has 3000 milliliters of water in it, but there is a hole that is leaking 18 milliliters every minute. How much water remains in the container after a certain number of minutes?

[tex]\[ y = 3000 - 18x \][/tex]

Answer :

To solve this problem, we need to find out how much water remains in the garden watering bucket after a certain number of minutes, given that the bucket initially contains 3000 milliliters of water and leaks 18 milliliters per minute.

Let's go through the steps to understand how to calculate it:

1. Initial Amount of Water:
- The bucket starts with 3000 milliliters of water.

2. Leakage Rate:
- Every minute, 18 milliliters of water leak from the bucket.

3. Calculate the Water Leaked:
- If we want to find out the amount of water leaked after a specific number of minutes, say [tex]\( x \)[/tex] minutes, we multiply the leakage rate by the number of minutes:
[tex]\[
\text{Leaked water} = 18 \times x
\][/tex]

4. Remaining Water:
- To find out how much water is left in the bucket after [tex]\( x \)[/tex] minutes, we subtract the leaked water from the initial amount:
[tex]\[
y = 3000 - 18x
\][/tex]
- Here, [tex]\( y \)[/tex] represents the remaining water in the bucket after [tex]\( x \)[/tex] minutes.

5. Example Calculation:
- For example, let's calculate how much water remains after 10 minutes:
- The water leaked after 10 minutes is [tex]\( 18 \times 10 = 180 \)[/tex] milliliters.
- Subtract this from the initial 3000 milliliters to get the remaining water:
[tex]\[
y = 3000 - 180 = 2820 \text{ milliliters}
\][/tex]

This step-by-step process helps us understand how to determine the remaining amount of water in the bucket after any given period of time.

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Rewritten by : Barada