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The perimeter of a triangle is 59 inches. The longest side is 11 inches longer than the medium side, and the medium side is 3 inches longer than the shortest side.

Find the length of each side of the triangle.

Answer :

let the length of shortest side be - x
length of medium side - x +3
length of longest side - x +3 + 11
so , according to question
=> x + x +3 + x +3 + 11 = 59
=> x + x +x + 3 + 3 + 11 = 59
=> 3x = 59 - 17
=> 3 x = 42
=> x = 42/3
=> x = 14
Shortest side = x = 14
medium side = x + 3 = 14+3 = 17
longest side = x + 3 +11 = 14 + 3 + 11 = 28

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Rewritten by : Barada

Final answer:

The shortest side of the triangle is 14 in, the medium side is 17 in, and the longest side is 28 in.

Explanation:

Let the shortest side be x in. The medium side is then x + 3 in. and the longest side is x + 14 in. Since the perimeter is 59 in., we can set up the equation:

x + (x + 3) + (x + 14) = 59

Combine like terms:

3x + 17 = 59

Subtract 17 from both sides:

3x = 42

Divide both sides by 3:

x = 14

So, the shortest side is 14 in., the medium side is 14 + 3 = 17 in., and the longest side is 14 + 14 = 28 in.