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Answer :
The car will skid a distance of 135 m with the brakes of the car producing the same deceleration.
What is an equation for motion?
A moving car has initial velocity (u), the final velocity of the car (v) with acceleration (a) with displacement (S). The relation for motion can be written as:
v²- u² = 2aS
When the brakes of a car apply, we want its final velocity zero. The displacement of the car after brakes are applied to stop it. The stopping distance of the car is proportional to the square of the initial velocity of the car.
Given, the initial velocity of the car = 50 km/h,
The car skids a distance with locked brakes = 15 m,
The car will skid a distance at speed of 150 km/h, = 15 m × (150/50)²
= 15 m × (3)²
= 15 m × 9
= 135 m
Therefore the stopping distance of the car with locked brakes at 150 km/h is 135 m.
Learn more about equations for motion, here:
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Rewritten by : Barada
Kinetic energy = (1/2 m) x (speed)²
A car moving 3 times as fast has 9 times as much kinetic energy.
If the force of friction between the tires and the ground
is the same at every speed, then the car has to go 9 times
as far to burn off the increased kinetic energy.
9 x 15m = 135 meters
A car moving 3 times as fast has 9 times as much kinetic energy.
If the force of friction between the tires and the ground
is the same at every speed, then the car has to go 9 times
as far to burn off the increased kinetic energy.
9 x 15m = 135 meters
